$@ and $* in ShellScript

$@ behaves like $* except that when quoted the arguments are broken up properly if there are spaces in them.

Take this script for example (taken from the linked answer):

for var in "$@"
doecho "$var"
done

Gives this:

$ sh test.sh 1 2 '3 4'
1
2
3 4

Now change "$@" to $*:

for var in $*
doecho "$var"
done

And you get this:

$ ./test.sh 1 2 '3 4'
1
2
3
4

#!/bin/bash

echo "=========== loop one ========"
for i in "$*"
do
    echo $i
done

echo "=========== loop two ========"
for i in "$@"
do
    echo $i
done

output:

┌──(gaurav㉿learning-ocean)-[~/shellscript-youtube]
└─$ ./commandline-args.sh gaurav saurav amit manish
=========== loop one ========
gaurav saurav amit manish
=========== loop two ========
gaurav
saurav
amit
manish

┌──(gaurav㉿learning-ocean)-[~/shellscript-youtube]
└─$ ./commandline-args.sh gaurav saurav amit "manish sharma"
=========== loop one ========
gaurav saurav amit manish sharma
=========== loop two ========
gaurav
saurav
amit
manish sharma